MHT CET · Physics · Kinetic Theory of Gases
Two gases A and B are at absolute temperatures 350 K and 420 K respectively. The ratio of average kinetic energy of the molecules of gas \(B\) to that of gas \(A\) is
- A \(6: 5\)
- B \(\sqrt{6}: \sqrt{5}\)
- C \(36: 25\)
- D \(5: 6\)
Answer & Solution
Correct Answer
(A) \(6: 5\)
Step-by-step Solution
Detailed explanation
\( \frac{E_{B}}{E_{A}} = \frac{T_{B}}{T_{A}} \) \( = \frac{420 \, \text{K}}{350 \, \text{K}} \)
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