MHT CET · Physics · Rotational Motion
Two discs of same mass ąnd same thickness (t) are made from two different materials of densities ' \(\mathrm{d}_1\) ' and ' \(\mathrm{d}_2\) ' respectively. The ratio of the moment of inertia \(\mathrm{I}_1\) to \(\mathrm{I}_2\) of two discs about an axis passing through the centre and perpendicular to the plane of disc is
- A \(\mathrm{d}_1: \mathrm{d}_2\)
- B \(\mathrm{d}_2: \mathrm{d}_1\)
- C \(1: \mathrm{d}_1 \mathrm{~d}_2\)
- D \(1: \mathrm{d}_1^2 \mathrm{~d}_2\)
Answer & Solution
Correct Answer
(B) \(\mathrm{d}_2: \mathrm{d}_1\)
Step-by-step Solution
Detailed explanation
The ratio of moments of inertia of two discs of the same mass and same thickness but of different densities is given by \(\frac{\mathrm{I}_1}{\mathrm{I}_2}=\frac{\mathrm{R}_1^2}{\mathrm{R}_2^2}=\frac{\mathrm{d}_2}{\mathrm{~d}_1}\)
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