MHT CET · Physics · Electromagnetic Induction
Two different coils of self inductance \(L_{1}\) and \(L_{2}\) are placed close to each other so that the effective flux in one coil is completely linked with other. If \(M\) is the mutual inductance between them, then
- A \(M=L_{1} / L_{2}\)
- B \(M=L_{1} L_{2}\)
- C \(M=\sqrt{L_{1} L_{2}}\)
- D \(M=\left(L_{1} L_{2}\right)^{2}\)
Answer & Solution
Correct Answer
(C) \(M=\sqrt{L_{1} L_{2}}\)
Step-by-step Solution
Detailed explanation
We know that, \(M=-\frac{e_{2}}{d i_{1} / d t}=-\frac{e_{1}}{d i_{2} / d t}\)
Also, \(e_{1}=-L_{1} \frac{d i_{1}}{d t}\) and \(e_{2}=-L_{2} \frac{d i_{2}}{d t}\)
\(\begin{array}{ll}
\Rightarrow & M^{2}=\frac{e_{1} e_{2}}{\left(\frac{d i_{1}}{d t}\right)\left(\frac{d i_{2}}{d t}\right)}=L_{1} L_{2} \\
\Rightarrow & M=\sqrt{L_{1} L_{2}}
\end{array}\)
Also, \(e_{1}=-L_{1} \frac{d i_{1}}{d t}\) and \(e_{2}=-L_{2} \frac{d i_{2}}{d t}\)
\(\begin{array}{ll}
\Rightarrow & M^{2}=\frac{e_{1} e_{2}}{\left(\frac{d i_{1}}{d t}\right)\left(\frac{d i_{2}}{d t}\right)}=L_{1} L_{2} \\
\Rightarrow & M=\sqrt{L_{1} L_{2}}
\end{array}\)
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