MHT CET · Physics · Thermodynamics
Two cylinders A and B fitted with piston contain equal amount of an ideal diatomic as at temperature ' \(T\) ' K . The piston of cylinder A is free to move while that of B is held fixed. The same amount of heat is given to the gas in each cylinder. If the rise temperature of the gas in A is ' \(\mathrm{dT}_{\mathrm{A}}\) ', then the rise in temperature of the gas in cylinder B is \(\left(\gamma=\frac{\dot{\mathrm{C}}_{\mathrm{P}}}{\mathrm{C}_{\mathrm{V}}}\right)\)
- A \(\quad 2 \mathrm{dT}_{\mathrm{A}}\)
- B \(\frac{\mathrm{dT}_{\mathrm{A}}}{2}\)
- C \(\gamma \mathrm{dT}_{\mathrm{A}}\)
- D \(\frac{\mathrm{dT}_{\mathrm{A}}}{\gamma}\)
Answer & Solution
Correct Answer
(C) \(\gamma \mathrm{dT}_{\mathrm{A}}\)
Step-by-step Solution
Detailed explanation
In cylinder A , heat is supplied at constant pressure while in B at constant volume
\(\begin{aligned}
& \mathrm{Q}_{\mathrm{A}}=\mathrm{Q}_{\mathrm{B}} \\
& \mathrm{nC}_{\mathrm{p}} \mathrm{dT}_{\mathrm{A}}=\mathrm{nC}_{\mathrm{v}} \mathrm{dT}_{\mathrm{B}} \\
& \mathrm{dT}_{\mathrm{B}}=\frac{\mathrm{C}_{\mathrm{p}}}{\mathrm{C}_{\mathrm{v}}} \mathrm{dT}_{\mathrm{A}}=\gamma \mathrm{dT}_{\mathrm{A}}
\end{aligned}\)
\(\begin{aligned}
& \mathrm{Q}_{\mathrm{A}}=\mathrm{Q}_{\mathrm{B}} \\
& \mathrm{nC}_{\mathrm{p}} \mathrm{dT}_{\mathrm{A}}=\mathrm{nC}_{\mathrm{v}} \mathrm{dT}_{\mathrm{B}} \\
& \mathrm{dT}_{\mathrm{B}}=\frac{\mathrm{C}_{\mathrm{p}}}{\mathrm{C}_{\mathrm{v}}} \mathrm{dT}_{\mathrm{A}}=\gamma \mathrm{dT}_{\mathrm{A}}
\end{aligned}\)
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