MHT CET · Physics · Magnetic Effects of Current
Two concentric circular coils of 10 turns each are situated in the same plane. Their radii are \(20 \mathrm{~cm}\) and \(40 \mathrm{~cm}\) and they carry respectively \(0.2 \mathrm{~A}\) and \(0.3 \mathrm{~A}\) current in opposite direction. The magnetic field at the centre is ( \(\mu_0=4 \pi \times 10^{-7}\) SI units)
- A \(4 \pi \times 10^{-7} \mathrm{~T}\)
- B \(5 \pi \times 10^{-7} \mathrm{~T}\)
- C \(2 \pi \times 10^{-5} \mathrm{~T}\)
- D \(7 \pi \times 10^{-6} \mathrm{~T}\)
Answer & Solution
Correct Answer
(B) \(5 \pi \times 10^{-7} \mathrm{~T}\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} \mathrm{B}_{\text {net }} & =\frac{\mu_0 \mathrm{n}_1 \mathrm{I}_1}{2 \mathrm{r}_1}-\frac{\mu_0 \mathrm{n}_2 \mathrm{I}_2}{2 \mathrm{r}_2} \\ & =\frac{10 \mu_0}{2}\left[\frac{0.2}{0.2}-\frac{0.3}{0.4}\right] \\ & =5 \times 4 \pi \times 10^{-7} \times 0.25 \\ & =5 \pi \times 10^{-7} \mathrm{~T}\end{aligned}\)
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