MHT CET · Physics · Electromagnetic Induction
Two coils P and Q are kept near each other. When no current flows through coil \(P\) and current increases in coil \(Q\) at the rate of \(10 \mathrm{~A} / \mathrm{s}\), the e.m.f. in coil \(P\) is 15 mV. When coil \(Q\) carries no current and current of 1.8 A flows through coil P, the magnetic flux linked with coil Q is
- A 1.8 mWb
- B \(2.7 \mathrm{mWb}\)
- C \(1.5 \mathrm{mWb}\)
- D 1 mWb
Answer & Solution
Correct Answer
(B) \(2.7 \mathrm{mWb}\)
Step-by-step Solution
Detailed explanation
\(M = \frac{E_P}{\frac{dI_Q}{dt}}\) \(M = \frac{15 \times 10^{-3} \mathrm{~V}}{10 \mathrm{~A/s}} = 1.5 \times 10^{-3} \mathrm{~H}\)
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