MHT CET · Physics · Electromagnetic Induction
Two coils P and Q are kept near each other. When no current flows through coil P and current increases in coil Q at the rate \(10 \mathrm{~A} / \mathrm{s}\), the emf in coil P is 12 mV . When coil Q carries no current and current of 1.5 A flows through coil P , the magnetic flux linked with the coil Q in mWb is
- A 0.9
- B 1.2
- C 1.5
- D 1.8
Answer & Solution
Correct Answer
(D) 1.8
Step-by-step Solution
Detailed explanation
\( M = \frac{\mathcal{E}_P}{dI_Q/dt} = \frac{12 \times 10^{-3} \mathrm{~V}}{10 \mathrm{~A/s}} = 1.2 \times 10^{-3} \mathrm{~H} \) \( \Phi_Q = M I_P = (1.2 \times 10^{-3} \mathrm{~H}) \times (1.5 \mathrm{~A}) = 1.8 \times 10^{-3} \mathrm{~Wb} \)
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