MHT CET · Physics · Electromagnetic Induction
Two coils have a mutual inductance of \(0.004 \mathrm{H}\). The current changes in the first coil according to equation \(\mathrm{I}=\mathrm{I}_0 \sin \omega \mathrm{t}\), where \(\mathrm{I}_0=10 \mathrm{~A}\) and \(\omega=50 \pi \mathrm{rad} \mathrm{s}^{-1}\). The maximum value of e.m.f. in the second coil in volt is
- A \(5 \pi\)
- B \(4 \pi\)
- C \(2.5 \pi\)
- D \(2 \pi\)
Answer & Solution
Correct Answer
(D) \(2 \pi\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \left|e_s\right|=M \frac{d_p}{d t} \\ & \left|e_s\right|=M \frac{d}{d t} I_0 \sin \omega t \\ & \left|e_s\right|=M I_0 \omega \cos \omega t \\ \therefore \quad & \left|e_s\right|_{\max }=M I_0 \omega=0.004 \times 10 \times 50 \pi \\ \therefore \quad & \left|e_s\right|_{\max }=(2 \pi) \text { volt }\end{aligned}\)
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