MHT CET · Physics · Electromagnetic Induction
Two coils have a mutual inductance \(0. 003 \mathrm{H}\). The current changes in the first coil according to equation \(\mathrm{I}=\mathrm{I}_0 \quad \sin \omega \mathrm{t}\), where \(\mathrm{I}_0=8 \mathrm{~A}\) and \(\omega=100 \pi \mathrm{rad} \mathrm{s}^{-1}\). The maximum value of e.m.f. in the second coil is
- A \(\quad 2 \pi \mathrm{~V}\)
- B \(2.4 \pi \mathrm{~V}\)
- C \(5 \pi \mathrm{~V}\)
- D \(7.2 \pi \mathrm{~V}\)
Answer & Solution
Correct Answer
(B) \(2.4 \pi \mathrm{~V}\)
Step-by-step Solution
Detailed explanation
\(\begin{array}{ll} & \left|e_s\right|=M \frac{d I_p}{d t} \\ & \left|e_s\right|=M \frac{d}{d t} I_0 \sin \omega t \\ & \left|e_s\right|=M I_0 \omega \cos \omega t \\ \therefore \quad & \left|e_s\right|_{\max }=M I_0 \omega=0.003 \times 8 \times 100 \pi \times 1 \\ \therefore \quad & \left|e_s\right|_{\max }=(2.4 \pi) \text { volt }\end{array}\)
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