MHT CET · Physics · Electromagnetic Induction
Two coils A and B are placed in a circuit. When current in the coil A changes by \(0.8 \mathrm{~A}\) the magnetic flux in coil \(\mathrm{B}\) changes by \(0.16 \mathrm{~Wb}\). The mutual inductance between the coils is
- A \(2 \mathrm{H}\)
- B \(20 \mathrm{H}\)
- C \(0.5 \mathrm{H}\)
- D \(0.2 \mathrm{H}\)
Answer & Solution
Correct Answer
(D) \(0.2 \mathrm{H}\)
Step-by-step Solution
Detailed explanation
The magnetic flux in coil B is given by,
\(\Phi=M i_1\)
where, \(M\) is the coefficient of mutual inductance, \(i_1\) is the current in coil A.
\(\Rightarrow M=\frac{\Phi}{i_1}=\frac{0.16 \mathrm{~Wb}}{0.8 \mathrm{~A}}=0.2 \mathrm{H}\)
\(\Phi=M i_1\)
where, \(M\) is the coefficient of mutual inductance, \(i_1\) is the current in coil A.
\(\Rightarrow M=\frac{\Phi}{i_1}=\frac{0.16 \mathrm{~Wb}}{0.8 \mathrm{~A}}=0.2 \mathrm{H}\)
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