MHT CET · Physics · Electromagnetic Induction
Two circuits \(A\) and \(B\) are connected to identical d.c. sources each of e.m.f. 10 volt. Self-inductances of circuits \(A\) and \(B\) are respectively \(L_A=10 H\) and \(L_B=10 \mathrm{mH}\). The total resistance of each circuit is \(40 \Omega\). The ratio of energy consumed in circuit A and circuit B to build up the current to steady value is
- A 800
- B 1000
- C 1200
- D 1400
Answer & Solution
Correct Answer
(B) 1000
Step-by-step Solution
Detailed explanation
\( \frac{U_A}{U_B} = \frac{\frac{1}{2}L_A I^2}{\frac{1}{2}L_B I^2} = \frac{L_A}{L_B} \) \( \frac{U_A}{U_B} = \frac{10 \text{ H}}{10 \times 10^{-3} \text{ H}} \)
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