MHT CET · Physics · Current Electricity
Two cells of e.m.f.s \(E_1\) and \(E_2\left(E_1>E_2\right)\) are connected as shown in figure.
When the potentiometer is connected between A and B , the balancing length of the potentiometer wire is 3.60 m . On connecting the potentiometer between A and C , the balancing length is 0.90 m . The ratio \(E_1 / E_2\) is
- A \(5:4\)
- B \(4: 3\)
- C \(3: 4\)
- D \(4: 5\)
Answer & Solution
Correct Answer
(B) \(4: 3\)
Step-by-step Solution
Detailed explanation
\(E_1 = k L_1\) \(E_1 = k (3.60)\)
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