MHT CET · Physics · Motion In Two Dimensions
Two cars of masses \(m_{1}\) and \(m_{2}\) are moving in circles of radii \(r_{1}\) and \(r_{2}\) respectively. Their speeds are such that they make complete circles in the same time \(\mathrm{t}\). The ratio of their centripetal force is
- A \(\mathrm{m}_{1}: \mathrm{m}_{2}\)
- B \(\mathrm{r}_{1}: \mathrm{r}_{2}\)
- C \(1: 1\)
- D \(\mathrm{~m}_{1} \mathrm{r}_{1}: \mathrm{m}_{2} \mathrm{r}_{2}\)
Answer & Solution
Correct Answer
(D) \(\mathrm{~m}_{1} \mathrm{r}_{1}: \mathrm{m}_{2} \mathrm{r}_{2}\)
Step-by-step Solution
Detailed explanation
\(F = m \omega^2 r = m \left(\frac{2\pi}{t}\right)^2 r = \frac{4\pi^2 m r}{t^2}\) \(\frac{F_1}{F_2} = \frac{\frac{4\pi^2 m_1 r_1}{t^2}}{\frac{4\pi^2 m_2 r_2}{t^2}}\)
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