MHT CET · Physics · Motion In Two Dimensions
Two cars of masses ' \(\mathrm{m}_{1}\) ', and ' \(\mathrm{m}_{2}\) ' are moving in the circles of radii ' \(\mathrm{r}_{1}\) ' and ' \(\mathrm{r}_{2}\) ' respectively. Their angular speeds ' \(\omega_{1}\) ' and ' \(\omega_{2}\) ' are such that they both complete one revolution in the same time ' \(\mathrm{t}\) '. The ratio of linear speed of ' \(\mathrm{m}_{1}\) ' to the linear speed of ' \(\mathrm{m}_{2}\) ' is
- A \(\mathrm{r}_{1}: \mathrm{r}_{2}\)
- B \(\mathrm{~T}_{1}^{2}: \mathrm{T}_{2}^{2}\)
- C \(\omega_{1}^{2}: \omega_{2}^{2}\)
- D \(\mathrm{~m}_{1}: \mathrm{m}_{2}\)
Answer & Solution
Correct Answer
(A) \(\mathrm{r}_{1}: \mathrm{r}_{2}\)
Step-by-step Solution
Detailed explanation
They complete one revolution in the same time.
\(\begin{array}{l}\therefore \omega_{1}=\omega_{2} \\\therefore \frac{V_{1}}{r_{1}}=\frac{V_{2}}{r_{2}} \\\therefore \frac{V_{1}}{V_{2}}=\frac{r_{1}}{r_{2}}\end{array}\)
\(\begin{array}{l}\therefore \omega_{1}=\omega_{2} \\\therefore \frac{V_{1}}{r_{1}}=\frac{V_{2}}{r_{2}} \\\therefore \frac{V_{1}}{V_{2}}=\frac{r_{1}}{r_{2}}\end{array}\)
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