MHT CET · Physics · Capacitance
Two capacitors of same capacity are first joined in series and then in parallel. The
ratio of resultant capacity in series to that in parallel combination will be
- A \(2: 1\)
- B \(1: 4\)
- C \(4: 1\)
- D \(1: 2\)
Answer & Solution
Correct Answer
(B) \(1: 4\)
Step-by-step Solution
Detailed explanation
Let individual capacity be \(C\). \(C_S = \left(\frac{1}{C} + \frac{1}{C}\right)^{-1} = \left(\frac{2}{C}\right)^{-1} = \frac{C}{2}\)
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