MHT CET · Physics · Capacitance
Two capacitors of \(100 \mu \mathrm{~F}\) and \(50 \mu \mathrm{~F}\) are connected in parallel. If the potential difference across \(100 \mu \mathrm{~F}\) is 20 V and across \(50 \mu \mathrm{~F}\) is 40 V , then the common potential of the parallel combination will be (same polarities of the capacitor connected together)
- A 20 V
- B 60 V
- C \(\frac{3}{80} \mathrm{~V}\)
- D \(\frac{80}{3} \mathrm{~V}\)
Answer & Solution
Correct Answer
(D) \(\frac{80}{3} \mathrm{~V}\)
Step-by-step Solution
Detailed explanation
\(Q_1 = C_1 V_1 = (100 \times 10^{-6} \mathrm{F})(20 \mathrm{V}) = 2000 \times 10^{-6} \mathrm{C}\) \(Q_2 = C_2 V_2 = (50 \times 10^{-6} \mathrm{F})(40 \mathrm{V}) = 2000 \times 10^{-6} \mathrm{C}\)
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