MHT CET · Physics · Motion In Two Dimensions
Two bodies of masses \(\mathrm{m}\) and \(3 \mathrm{~m}\) are rotating in horizontal circles of radius \(r\) and \(\frac{r}{3}\) respectively. The tangential speed of body of mass \(m\) is \(n\) times that of the value of heavier body. while the centripetal force is same for both. The value of \(n\) is
- A 3
- B 9
- C 1
- D 6
Answer & Solution
Correct Answer
(A) 3
Step-by-step Solution
Detailed explanation
Centripetal force is same on both, therefore:
\(\begin{aligned} & \frac{m(n v)^2}{r}=\frac{3 m v^2}{\left(\frac{r}{3}\right)} \\ & \Rightarrow n^2=9 \\ & \Rightarrow n=3\end{aligned}\)
\(\begin{aligned} & \frac{m(n v)^2}{r}=\frac{3 m v^2}{\left(\frac{r}{3}\right)} \\ & \Rightarrow n^2=9 \\ & \Rightarrow n=3\end{aligned}\)
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