MHT CET · Physics · Current Electricity
Two batteries of e.m.f 4 V and 8 V with internal resistance \(1 \Omega\) and \(2 \Omega\) respectively are connected in a circuit with a resistance of \(9 \Omega\) as shown in the figure. The current and potential difference between the points ' P ' and ' Q ' is
- A \(\frac{1}{3} \mathrm{~A}\) and 4 V
- B \(\frac{1}{3} \mathrm{~A}\) and 3 V
- C \(\frac{1}{2} \mathrm{~A}\) and 5 V
- D \(\frac{1}{6} \mathrm{~A}\) and 3 V
Answer & Solution
Correct Answer
(B) \(\frac{1}{3} \mathrm{~A}\) and 3 V
Step-by-step Solution
Detailed explanation
\(I = \frac{\mathcal{E}_{net}}{R_{total}}\) \(I = \frac{(8 - 4) \mathrm{~V}}{(9 + 1 + 2) \Omega}\)
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