MHT CET · Physics · Current Electricity
To determine the internal resistance of a cell with potentiometer, when the cell is shunted by a resistance of \(5 \Omega\), the balancing length is 250 cm . When the cell is shunted by \(20 \Omega\), the balancing length of potentiometer wire is 400 cm . The internal resistance of the cell is
- A \(3 \Omega\)
- B \(4 \Omega\)
- C \(5 \Omega\)
- D \(6 \Omega\)
Answer & Solution
Correct Answer
(C) \(5 \Omega\)
Step-by-step Solution
Detailed explanation
\( \frac{L_1}{L_2} = \frac{R_1(R_2+r)}{R_2(R_1+r)} \) \( \frac{250}{400} = \frac{5(20+r)}{20(5+r)} \)
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