MHT CET · Physics · Gravitation
Time period of a simple pendulum on earth's surface is 'T'. It time period becomes 'xT' when taken to a height '2R' above earth's surface. The value of \(x\) will be ( \(R=\) radius of earth)
- A \(2\)
- B \(4\)
- C \(1\)
- D \(3\)
Answer & Solution
Correct Answer
(D) \(3\)
Step-by-step Solution
Detailed explanation
\(T \propto \frac{1}{\sqrt{g}}\) \(g_h = g \left(\frac{R}{R+h}\right)^2\)
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