MHT CET · Physics · Mathematics in Physics
Three vectors \(\vec{A}, \vec{B}\) and \(\vec{C}\) are such that \(\vec{A} \cdot \vec{B}=\vec{A} \cdot \vec{C}=0\), then \(\vec{A}\) is parallel to
\(\left[\cos 90^{\circ}=0\right]\)
- A \(\overrightarrow{\mathrm{B}} \cdot \overrightarrow{\mathrm{C}}\)
- B \(\overrightarrow{\mathrm{B}} \times \overrightarrow{\mathrm{C}}\)
- C \(\overrightarrow{\mathrm{C}}\)
- D \(\overrightarrow{\mathrm{B}}\)
Answer & Solution
Correct Answer
(B) \(\overrightarrow{\mathrm{B}} \times \overrightarrow{\mathrm{C}}\)
Step-by-step Solution
Detailed explanation
\(\vec{A} \cdot \vec{B}=0 \implies \vec{A} \perp \vec{B}\) \(\vec{A} \cdot \vec{C}=0 \implies \vec{A} \perp \vec{C}\)
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