MHT CET · Physics · Rotational Motion
Three spheres, each of mass ' \(m\) ' and radius ' \(r\) ' are placed as shown in figure. Consider an axis \(\mathrm{YY}^1\), which is touching two spheres and passing through the diameter of third sphere. The moment of inertia of the system consisting of these three spheres about \(\mathrm{YY}^1\) axis is
- A \(\frac{7}{5} \mathrm{mr}^2\)
- B \(\frac{2}{5} \mathrm{mr}^2\)
- C \(\frac{16}{5} \mathrm{mr}^2\)
- D \(\frac{\mathrm{mr}^2}{2}\)
Answer & Solution
Correct Answer
(C) \(\frac{16}{5} \mathrm{mr}^2\)
Step-by-step Solution
Detailed explanation
\(I_{diameter} = \frac{2}{5}mr^2\) \(I_{tangent} = I_{CM} + md^2 = \frac{2}{5}mr^2 + m(r)^2 = \frac{7}{5}mr^2\)
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