MHT CET · Physics · Rotational Motion
Three points masses, each of mass 'm' are placed at the corners of an equilateral triangle of side \(\ell^{\prime}\). The moment of inertia of the system about an axis passing through one of the vertices and parallel to the side joining other two vertices, will be
- A \(\frac{3}{2} \mathrm{~m} \ell^{2}\)
- B \(\frac{3}{4} \mathrm{~m} \ell^{2}\)
- C \(\frac{1}{2} \mathrm{~m} \ell^{2}\)
- D \(\frac{1}{4} \mathrm{~m} \ell^{2}\)
Answer & Solution
Correct Answer
(A) \(\frac{3}{2} \mathrm{~m} \ell^{2}\)
Step-by-step Solution
Detailed explanation
\(I =2 \mathrm{mh}^{2}\)
\(\mathrm{h}=\ell \sin 60^{\circ}=\ell \times \frac{\sqrt{3}}{2}\)
\(I =2 \mathrm{~m} \times \frac{3}{4} \cdot \ell^{2}=\frac{3}{2} \mathrm{~m} \ell^{2}\)

\(\mathrm{h}=\ell \sin 60^{\circ}=\ell \times \frac{\sqrt{3}}{2}\)
\(I =2 \mathrm{~m} \times \frac{3}{4} \cdot \ell^{2}=\frac{3}{2} \mathrm{~m} \ell^{2}\)

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