MHT CET · Physics · Electrostatics
Three point charges \(+Q+2 Q\) and \(q\) are placed at the vertices of an equilateral triangle. The value of charge q in terms of Q , so that electrical potential energy of the system is zero, is given by
- A \(\mathrm{q}=\frac{1}{3} \mathrm{Q}\)
- B \(\mathrm{q}=\frac{2}{3} \mathrm{Q}\)
- C \(\mathrm{q}=-\frac{2}{3} \mathrm{Q}\)
- D \(\mathrm{q}=-\frac{3}{2} \mathrm{Q}\)
Answer & Solution
Correct Answer
(C) \(\mathrm{q}=-\frac{2}{3} \mathrm{Q}\)
Step-by-step Solution
Detailed explanation
\(U_{total} = \frac{k(Q)(2Q)}{a} + \frac{k(Q)(q)}{a} + \frac{k(2Q)(q)}{a} = 0\) \(2Q^2 + Qq + 2Qq = 0\)
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