MHT CET · Physics · Ray Optics
Three immiscible transparent liquids with uniform refractive indices \(\frac{3}{2}, \frac{4}{3}\) and \(\frac{6}{5}\) are arranged one on top of another. The depths of the liquids are 3 cm 4 cm and 6 cm respectively. The apparent depth of the vessel is
- A 10 cm
- B 9 cm
- C 8 cm
- D 7 cm
Answer & Solution
Correct Answer
(A) 10 cm
Step-by-step Solution
Detailed explanation
\(\mu=\frac{\text { Real depth }(R)}{\text { Apparent depth }} \Rightarrow \text { Apparent depth }=\frac{R}{\mu}\)
For vessel,
\(\begin{aligned}
\text { Apparent depth } & =\frac{R_1}{\mu_1}+\frac{R_2}{\mu_2}+\frac{R_3}{\mu_3} \\
& =\frac{3}{3 / 2}+\frac{4}{4 / 3}+\frac{6}{6 / 5} \\
& =2+3+5 \\
\text { Apparent depth } & =10 \mathrm{~cm}
\end{aligned}\)
For vessel,
\(\begin{aligned}
\text { Apparent depth } & =\frac{R_1}{\mu_1}+\frac{R_2}{\mu_2}+\frac{R_3}{\mu_3} \\
& =\frac{3}{3 / 2}+\frac{4}{4 / 3}+\frac{6}{6 / 5} \\
& =2+3+5 \\
\text { Apparent depth } & =10 \mathrm{~cm}
\end{aligned}\)
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