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MHT CET · Physics · Capacitance

Three identical capacitors of capacitance ' \(\mathrm{C}\) ' each are connected in series and this connection is connected in parallel with one more such identical capacitor. Then the capacitance of whole combination is

  1. A \(3 \mathrm{C}\)
  2. B \(2 \mathrm{C}\)
  3. C \(\frac{4}{3} \mathrm{C}\)
  4. D \(\frac{3}{4} C\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(\frac{4}{3} \mathrm{C}\)

Step-by-step Solution

Detailed explanation

The equivalent capacitance of three capacitances connected in series is
\(\begin{aligned}
& \frac{1}{\mathrm{C}_{\text {eq }}}=\frac{1}{\mathrm{C}}+\frac{1}{\mathrm{C}}+\frac{1}{\mathrm{C}} \\
& \frac{1}{\mathrm{C}_{\text {eq }}}=\frac{3}{\mathrm{C}} \\
& \mathrm{C}_{\text {eq }}=\frac{\mathrm{C}}{3}
\end{aligned}\)
This capacitance is connected in parallel with another capacitance.
\(\begin{aligned}
& \Rightarrow C_{\text {tatal }}=\frac{C}{3}+C \\
& C_{\text {teal }}=\frac{4 C}{3}
\end{aligned}\)