MHT CET · Physics · Capacitance
Three condenser of capacitance \(C(\mu \mathrm{F})\) are connected in parallel to which a condenser of capacitance \(C\) is connected in series. Effective capacitance is \(3.75\), then capacity of each condenser is
- A \(4 \mu \mathrm{F}\)
- B \(5 \mu \mathrm{F}\)
- C \(6 \mu \mathrm{F}\)
- D \(8 \mu \mathrm{F}\)
Answer & Solution
Correct Answer
(B) \(5 \mu \mathrm{F}\)
Step-by-step Solution
Detailed explanation
The effective capacitance of three condenser connected in parallel \(=3 C\) When \(3 C\) is connected in series to \(C\)
\(
\begin{aligned}
C_{\text {Result }} &=\frac{3 C \times C}{3 C+C}=3.75 \\
\Rightarrow \quad C &=5 \mu \mathrm{F}
\end{aligned}
\)
\(
\begin{aligned}
C_{\text {Result }} &=\frac{3 C \times C}{3 C+C}=3.75 \\
\Rightarrow \quad C &=5 \mu \mathrm{F}
\end{aligned}
\)
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