MHT CET · Physics · Electrostatics
Three charges \(q, Q\) and \(+4 q\) are placed in a straight line of length \(d\) at points at distances \(0, \frac{d}{2}\) and d respectively. In order to make the net force on \(q\) to be zero, the value of \(Q\) should be
- A \(-2 q\)
- B \(\frac{-q}{2}\)
- C \(-q\)
- D \(\frac{-3}{2} q\)
Answer & Solution
Correct Answer
(C) \(-q\)
Step-by-step Solution
Detailed explanation
Consider the diagram below:
To make net force on \(q\) is zero, charge \(Q\) should be negative.
\(\begin{aligned}
& \therefore \frac{k q Q}{\left(\frac{d}{2}\right)^2}+\frac{k q(4 q)}{d^2}=0 \\
& \Rightarrow Q=-q
\end{aligned}\)
To make net force on \(q\) is zero, charge \(Q\) should be negative.
\(\begin{aligned}
& \therefore \frac{k q Q}{\left(\frac{d}{2}\right)^2}+\frac{k q(4 q)}{d^2}=0 \\
& \Rightarrow Q=-q
\end{aligned}\)
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