MHT CET · Physics · Electrostatics
Three charges each of \(+1 \mu \mathrm{C}\) are placed at the corners of an equilateral triangle. If the repulsive force between any two charges is \(\mathrm{F}\), then the net force on either charge will be
- A \(2 \mathrm{~F}\)
- B \(3 \mathrm{~F}\)
- C \(\sqrt{2} \mathrm{~F}\)
- D \(\sqrt{3} \mathrm{~F}\)
Answer & Solution
Correct Answer
(D) \(\sqrt{3} \mathrm{~F}\)
Step-by-step Solution
Detailed explanation
The force on any charge due to each of the other two charges has magnitude \(\mathrm{F}\).
The angle between the two forces is \(60^{\circ}\).
Hence the resultant force is given by
\(R=\sqrt{F^2+F^2+2 F^2 \cos 60^{\circ}}=\sqrt{3} F\)
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