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MHT CET · Physics · Electrostatics

Three charges ' +3 q ' , ' Q ' and ' +q ' are placed in a straight line of length ' \(\ell\) ' at points at distances \(0, \frac{\ell}{2}\) and \(\ell\) respectively. The value of \(Q\) in order to have the net force on \(+q\) to be zero, \(Q=x q\). The value of \(x\) is

  1. A \(-\frac{1}{4}\)
  2. B \(\frac{-3}{4}\)
  3. C \(-3\)
  4. D \(4\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(\frac{-3}{4}\)

Step-by-step Solution

Detailed explanation

\(F_{net} = F_{3q \to q} + F_{Q \to q} = 0\) \(k \frac{(+3q)(+q)}{\ell^2} + k \frac{Q(+q)}{(\ell/2)^2} = 0\)
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