MHT CET · Physics · Center of Mass Momentum and Collision
Three bodies each of mass \(1 \mathrm{~kg}\) are situated at the vertices of an equilateral triangle of side \(1 \mathrm{~m}\). The \(x y\)-coordinates of centre of mass of the system are.
- A \(\left(\frac{1}{2 \sqrt{3}}, \frac{1}{2 \sqrt{3}}\right)\)
- B \(\left(\frac{1}{2 \sqrt{3}}, \frac{1}{2}\right)\)
- C \(\left(\frac{1}{2}, \frac{1}{2}\right)\)
- D \(\left(\frac{1}{2}, \frac{1}{2 \sqrt{3}}\right)\)
Answer & Solution
Correct Answer
(D) \(\left(\frac{1}{2}, \frac{1}{2 \sqrt{3}}\right)\)
Step-by-step Solution
Detailed explanation

\(\begin{aligned} & X_{\mathrm{cm}}=\frac{0+(1 \times 1)+(1 \times 0.5)}{3}=\frac{1}{2} \mathrm{~m} \\ & Y_{\mathrm{cm}}=\frac{0+0+\left(1 \times \frac{\sqrt{3}}{2}\right)}{3}=\frac{1}{2 \sqrt{3}} \mathrm{~m}\end{aligned}\)
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