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MHT CET · Physics · Thermal Properties of Matter

Three black discs \(x, y, z\) have radii \(1 \mathrm{~m}, 2 \mathrm{~m}\) and \(3 \mathrm{~m}\) respectively. The wavelength corresponding to maximum intensity are \(200 \mathrm{~nm}\), \(300 \mathrm{~nm}\) and \(400 \mathrm{~nm}\) respectively. The relation between emissive power \(E_x, E_y\) and \(E_z\) is

  1. A \(E_x\) is maximum
  2. B \(E_y\) is maximum
  3. C \(E_z\) is maximum
  4. D \(E_x=E_y=E_z\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(E_x\) is maximum

Step-by-step Solution

Detailed explanation

According to the Stefan's Law:
\(\begin{aligned}
& E=\frac{\sigma A T^4}{A} \\
& \Rightarrow E \propto T^4
\end{aligned}\)
According to the Wein's Law:
\(\begin{aligned}
& T=\frac{k}{\lambda_m} \\
& \therefore E \propto \frac{A}{\lambda^4} \\
& E_x: E_y: E_z=\frac{1}{\lambda_x^4}: \frac{1}{\lambda^4}: \frac{1}{\lambda^4}=\frac{1}{200^4}: \frac{1}{300^4}: \frac{1}{400^4}
\end{aligned}\)
The relation between emissive power \(E_x, E_y\) and \(E_z\) is as follows:
\(E x>E y>E z\)