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MHT CET · Physics · Center of Mass Momentum and Collision

There is head-on elastic collision between the two particles moving in the same direction with speeds \(5 \mathrm{~m} / \mathrm{s}\) and \(3 \mathrm{~m} / \mathrm{s}\) respectively. After collision, the velocity of the first particle becomes \(4 \mathrm{~m} / \mathrm{s}\) in the same direction. The velocity of the second particle should be

  1. A \(6 \mathrm{~m} / \mathrm{s}\) in the same direction.
  2. B \(4 \mathrm{~m} / \mathrm{s}\) in the same direction.
  3. C \(2 \mathrm{~m} / \mathrm{s}\) in the opposite direction.
  4. D \(3 \mathrm{~m} / \mathrm{s}\) in the same direction.
Verified Solution

Answer & Solution

Correct Answer

(A) \(6 \mathrm{~m} / \mathrm{s}\) in the same direction.

Step-by-step Solution

Detailed explanation

\(u_1 - u_2 = v_2 - v_1\) \(5 - 3 = v_2 - 4\)