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MHT CET · Physics · Dual Nature of Matter

The work functions for metals A, B and C are \(1.92 \mathrm{eV}, 2.0 \mathrm{eV}\) and \(5 \mathrm{eV}\) respectively the metal (s) which will emit photoelectrons for incident radiation of wavelength \(4100 \mathrm{~A}\) is /are \([\mathrm{h}=6.63 \times 10^{-19} \mathrm{~J}, \mathrm{e}=1.6 \times 10^{-19} \mathrm{C}, \mathrm{c}=3\) \(\times 10^8 \mathrm{~m} / \mathrm{s}]\)

  1. A Only C
  2. B B and C
  3. C Only A
  4. D \(A\) and \(B\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(A\) and \(B\)

Step-by-step Solution

Detailed explanation

Energy of electron with an associated wavelength of \(4100\)Å is:
\(\Rightarrow \frac{\mathrm{hc}}{\lambda}=4.845 \times 10^{-19} \mathrm{~J}=3.024 \mathrm{eV}\)
This incident electron would emit photon from metal whose work potential is less than its energy.
Thus, it would emit photons from metals A and B.
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