MHT CET · Physics · Mechanical Properties of Fluids
The work done in splitting a water drop of radius \(R\) in to 64 droplets is ( \(\mathrm{T}=\) surface tension of water)
- A \(6 \pi \mathrm{TR}^2\)
- B \(24 \pi \mathrm{TR}^2\)
- C \(12 \pi \mathrm{TR}^2\)
- D \(16 \pi \mathrm{TR}^2\)
Answer & Solution
Correct Answer
(C) \(12 \pi \mathrm{TR}^2\)
Step-by-step Solution
Detailed explanation
\(r = R/4\) \(\Delta A = 64(4\pi r^2) - 4\pi R^2\)
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