MHT CET · Physics · Mechanical Properties of Fluids
The work done in blowing a soap bubble of volume ' \(\mathrm{V}\) ' is ' \(\mathrm{W}\) '. The work required to blow a soap bubble of volume ' \(2 \mathrm{~V}\) ' is [ \(\mathrm{T}=\) surface tension of soap solution \(]\)
- A \(2^{2 / 3} \mathrm{~W}\)
- B 2W
- C W
- D \(2^{1 / 2} \mathrm{~W}\)
Answer & Solution
Correct Answer
(A) \(2^{2 / 3} \mathrm{~W}\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \mathrm{V}=\frac{4}{3} \pi \mathrm{r}^3 \text { or } \quad \mathrm{r}=\left(\frac{3 \mathrm{~V}}{4 \pi}\right)^{1 / 3} \\ & \mathrm{~W}=8 \pi \mathrm{r}^2 \mathrm{~T}=8 \pi\left(\frac{3 \mathrm{~V}}{4 \pi}\right)^{2 / 3} \mathrm{~T} \\ & \mathrm{~W} \propto \mathrm{V}^{2 / 3} \\ & \frac{\mathrm{W}^{\prime}}{\mathrm{W}}=\left(\frac{2 \mathrm{~V}}{\mathrm{~V}}\right)^{2 / 3}=2^{2 / 3}\end{aligned}\)
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