MHT CET · Physics · Magnetic Effects of Current
The wire loop PQRSP formed by joining two semicircular wire of radii \(R_1\) and \(R_2\) carries a current \(I\) as shown. The magnitude of the magnetic field at the centre ' 0 ' is
- A \(\frac{\mu_0 \mathrm{I}}{4}\left[\frac{1}{\mathrm{R}_1}-\frac{1}{\mathrm{R}_2}\right]\)
- B \(\frac{\mu_0 \mathrm{I}}{4}\left[\frac{1}{\mathrm{R}_2}-\frac{1}{\mathrm{R}_1}\right]\)
- C \(\frac{\mu_0 \mathrm{I}}{2 \pi}\left[\frac{1}{\mathrm{R}_1}-\frac{1}{\mathrm{R}_2}\right]\)
- D \(\frac{\mu_0 \mathrm{I}}{2 \pi}\left[\frac{1}{\mathrm{R}_2}-\frac{1}{\mathrm{R}_1}\right]\)
Answer & Solution
Correct Answer
(B) \(\frac{\mu_0 \mathrm{I}}{4}\left[\frac{1}{\mathrm{R}_2}-\frac{1}{\mathrm{R}_1}\right]\)
Step-by-step Solution
Detailed explanation
\(B_{net} = B_{inner} - B_{outer}\) \(B_{net} = \frac{\mu_0 I}{4R_2} - \frac{\mu_0 I}{4R_1}\)
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