MHT CET · Physics · Laws of Motion
The weight of man in a stationary lift is \(\mathrm{w}_1\) and when it is moving downwards with uniform acceleration ' \(a\) ' is \(w_2\). If the ratio \(\mathrm{w}_1: \mathrm{w}_2=4: 3\), then the value of ' a ' is ( \(\mathrm{g}=\) acceleration due to gravity)
- A \(\frac{g}{3}\)
- B \(\frac{g}{4}\)
- C \(\frac{3}{4} \mathrm{~g}\)
- D \(\frac{4}{g}\)
Answer & Solution
Correct Answer
(B) \(\frac{g}{4}\)
Step-by-step Solution
Detailed explanation
\(w_1 = mg\) \(w_2 = m(g - a)\)
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