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MHT CET · Physics · Atomic Physics

The wavelength of light for the least energetic photons emitted in the Lyman series of the hydrogen spectrum is nearly [Take \(\mathrm{hc}=1240 \mathrm{eV}-\mathrm{nm}\), change in energy of the levels \(=10.2 \mathrm{eV}]\)

  1. A \(150 \mathrm{~nm}\)
  2. B \(122 \mathrm{~nm}\)
  3. C \(102 \mathrm{~nm}\)
  4. D \(82 \mathrm{~nm}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(122 \mathrm{~nm}\)

Step-by-step Solution

Detailed explanation

For least energetic photon emitted in Lyman series, \(E=E_2-E_1=10.2 \mathrm{eV}\)
\(\begin{aligned}
\lambda=\frac{\mathrm{hc}}{\mathrm{E}} & =\frac{1240}{10.2} \mathrm{~nm} \\
& =121.57 \mathrm{~nm} \approx 122 \mathrm{~nm}
\end{aligned}\)
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