MHT CET · Physics · Dual Nature of Matter
The wavelength ' \(\lambda\) ' of a photon and the de-Broglie wavelength of an electron have same value. the ratio of kinetic energy of the electron to the energy of a photon is
( \(\mathrm{m}=\) mass of electron, \(\mathrm{c}=\) velocity of light, \(\mathrm{h}=\) Planck's constant)
- A \(\frac{2 \lambda m c}{h}\)
- B \(\frac{\lambda \mathrm{mc}}{\mathrm{h}}\)
- C \(\frac{h}{2 \lambda m c}\)
- D \(\frac{\mathrm{h}}{\lambda \mathrm{mc}}\)
Answer & Solution
Correct Answer
(C) \(\frac{h}{2 \lambda m c}\)
Step-by-step Solution
Detailed explanation
\(E_p = \frac{hc}{\lambda}\) \(p_e = \frac{h}{\lambda}\)
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