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MHT CET · Physics · Atomic Physics

The wave number of the last line of the Balmer series in the hydrogen spectrum will be (Rydberg'sconstnat, \(\left.\mathrm{R}=\frac{10^7}{\mathrm{~m}}\right)\)

  1. A \(16 \times 10^4 \mathrm{~m}^{-1}\)
  2. B \(8 \times 10^5 \mathrm{~m}^{-1}\)
  3. C \(36 \times 10^7 \mathrm{~m}^{-1}\)
  4. D \(25 \times 10^5 \mathrm{~m}^{-1}\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(25 \times 10^5 \mathrm{~m}^{-1}\)

Step-by-step Solution

Detailed explanation

The wave number of the last line of the Balmer series is given by \(\frac{1}{\lambda}=\frac{\mathrm{R}}{4}=\frac{10^7}{4}=25 \times 10^5 \mathrm{~m}^{-1}\)