MHT CET · Physics · Capacitance
The voltage between the plates of a parallel plate capacitor of capacity \(1 \mu \mathrm{~F}\) is changing at the rate of \(4 \mathrm{~V} / \mathrm{s}\). the displacement current in the capacitor is
- A \(4 ~\mu \mathrm{A}\)
- B \(3 ~\mu \mathrm{A}\)
- C \(1 ~\mu \mathrm{A}\)
- D \(6 ~\mu \mathrm{A}\)
Answer & Solution
Correct Answer
(A) \(4 ~\mu \mathrm{A}\)
Step-by-step Solution
Detailed explanation
\(I_d = C \frac{dV}{dt}\) \(I_d = (1 \times 10^{-6} \, \mathrm{F}) \times (4 \, \mathrm{V/s})\)
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