MHT CET · Physics · Current Electricity
The value of the shunt resistance that allows \(10 \%\) of the main current through the galvanometer of \(99 \Omega\) is
- A \(9 \Omega\)
- B \(11 \Omega\)
- C \(13 \Omega\)
- D \(15 \Omega\)
Answer & Solution
Correct Answer
(B) \(11 \Omega\)
Step-by-step Solution
Detailed explanation
\(I_g G = (I - I_g) S\) \(0.1 I \times 99 \, \Omega = (I - 0.1 I) S\)
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