MHT CET · Physics · Gravitation
The value of acceleration due to gravity at a depth ' \(d\) ' from the surface of earth and at an altitude ' \(h\) ' from the surface of earth are in the ratio
- A \(1: 1\)
- B \(\frac{R-2 h}{R-d}\)
- C \(\frac{R-d}{R-2 h}\)
- D \(\frac{R-d}{R-h}\)
Answer & Solution
Correct Answer
(C) \(\frac{R-d}{R-2 h}\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \frac{g_d}{g_h}=\frac{g\left[1-\frac{d}{R}\right]}{g\left[1-\frac{2 h}{R}\right]} \\ & \frac{g_d}{g_h}=\frac{R-d}{R-2 h}\end{aligned}\)
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