MHT CET · Physics · Semiconductors
The truth-table for the two-input Ex-OR gate is (A, B are the inputs, \(\mathrm{Y}\) is the output).
- A P
- B Q
- C R
- D S
Answer & Solution
Correct Answer
(D) S
Step-by-step Solution
Detailed explanation
The Boolean expression for Exclusive-OR gate is as follows:
\(Y=(A \oplus B)=\bar{A} \cdot B+A \cdot \bar{B}\)"ō"
The output of an Exclusive-OR gate ONLY goes "HIGH" when its two input terminals are at "DIFFERENT" logic levels with respect to each other.
Therefore, option table S is correct.
\(Y=(A \oplus B)=\bar{A} \cdot B+A \cdot \bar{B}\)"ō"
The output of an Exclusive-OR gate ONLY goes "HIGH" when its two input terminals are at "DIFFERENT" logic levels with respect to each other.
Therefore, option table S is correct.
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