MHT CET · Physics · Kinetic Theory of Gases
The translational kinetic energy of the molecules of a gas at absolute temperature \(T\) can be doubled by
- A decreasing \(T\) to \(\frac{T}{2}\)
- B increasing \(T\) to \(4 T\)
- C increasing \(T\) to \(\sqrt{2} T\)
- D increasing \(T\) to \(2 T\)
Answer & Solution
Correct Answer
(D) increasing \(T\) to \(2 T\)
Step-by-step Solution
Detailed explanation
The average translational kinetic energy \(K\) is proportional to \(T\). So, to double the \(K\), temperature has to be doubled.
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