MHT CET · Physics · Oscillations
The time taken by a particle executing simple harmonic motion of period \(T\) to move from the mean position to half the maximum displacement is
- A \(\frac{T}{2} s\)
- B \(\frac{T}{12} s\)
- C \(\frac{T}{6} s\)
- D \(\frac{T}{4} s\)
Answer & Solution
Correct Answer
(B) \(\frac{T}{12} s\)
Step-by-step Solution
Detailed explanation
Let at the instant \(t=0\), the particle is at the mean position.
So, the displacement equation of the particle executing SHM is given by, \(x=A \sin (\omega t))\)
Where, \(A\) and ware the amplitude of oscillation and the frequency respectively.
Let the time taken by the particle in going from mean position to half maximum displacement be .
So, the displacement equation of the particle executing SHM is given by, \(x=A \sin (\omega t))\)
Where, \(A\) and ware the amplitude of oscillation and the frequency respectively.
Let the time taken by the particle in going from mean position to half maximum displacement be .
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