MHT CET · Physics · Dual Nature of Matter
The threshold wavelengths for photoelectric emission from two metals \(\mathrm{A}\) and \(\mathrm{B}\)
are \(400 \mathrm{~nm}\) and \(800 \mathrm{~nm}\) respectively. The ratio of their work functions, \(\phi_{A}\) to \(\phi\) ?
is
- A \(\frac{1}{2}\)
- B 4
- C \(\frac{1}{4}\)
- D 2
Answer & Solution
Correct Answer
(D) 2
Step-by-step Solution
Detailed explanation
(D)
work function \(\phi=\frac{h c}{\lambda_{0}}\)
\(\therefore \frac{\phi_{B}}{\phi_{A}}=\frac{\lambda_{B}}{\lambda_{A}}=\frac{800}{400}=2\)
work function \(\phi=\frac{h c}{\lambda_{0}}\)
\(\therefore \frac{\phi_{B}}{\phi_{A}}=\frac{\lambda_{B}}{\lambda_{A}}=\frac{800}{400}=2\)
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