MHT CET · Physics · Kinetic Theory of Gases
The temperature of an ideal gas is increased from 100 K to 400 K. If ' x ' is the R.M.S. velocity of its molecules at 100 K, it becomes
- A \(\frac{x}{4}\)
- B \(2 x\)
- C \(3 x\)
- D \(4 x\)
Answer & Solution
Correct Answer
(B) \(2 x\)
Step-by-step Solution
Detailed explanation
\( \frac{v_2}{v_1} = \sqrt{\frac{T_2}{T_1}} \) \( v_2 = x \sqrt{\frac{400}{100}} = x \sqrt{4} = 2x \)
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