MHT CET · Physics · Kinetic Theory of Gases
The temperature at which oxygen molecules will have same r.m.s. speed as helium molecules at \(57^{\circ} \mathrm{C}\) is (molecular masses of oxygen and helium are 32 and 4 respectively.)
- A 1320 K
- B 2240 K
- C 2640 K
- D 3230 K
Answer & Solution
Correct Answer
(C) 2640 K
Step-by-step Solution
Detailed explanation
\(T_{He} = 57 + 273 = 330 \mathrm{K}\) \(v_{rms, O_2} = v_{rms, He} \implies \frac{T_{O_2}}{M_{O_2}} = \frac{T_{He}}{M_{He}}\)
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