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MHT CET · Physics · Kinetic Theory of Gases

The temperature at which oxygen molecules will have same r.m.s. speed as helium molecules at \(57^{\circ} \mathrm{C}\) is (molecular masses of oxygen and helium are 32 and 4 respectively.)

  1. A 1320 K
  2. B 2240 K
  3. C 2640 K
  4. D 3230 K
Verified Solution

Answer & Solution

Correct Answer

(C) 2640 K

Step-by-step Solution

Detailed explanation

\(T_{He} = 57 + 273 = 330 \mathrm{K}\) \(v_{rms, O_2} = v_{rms, He} \implies \frac{T_{O_2}}{M_{O_2}} = \frac{T_{He}}{M_{He}}\)